1. x pangkat 2-5x-6 per x+1 2. 3x pangkat 2-27 per x pangkat 2+2x-3 3. 2x pangkat 2+3x-9 per x pangkat 2+2x-3

[tex] \frac{x^{2} - 5x - 6}{x + 1} = \frac{(x + 1)(x - 6)}{(x +1)} = x + 6 \\ \\ \frac{3x^{2} - 27}{x^{2} + 2x - 3} = \frac{3(x - 3)(x + 3)}{(x - 1)(x + 3)} = \frac{3x - 9}{x - 1} \\ \\ \frac{2x^{2} + 3x - 9}{x^{2} + 2x -3} = \frac{(2x - 3)(x + 3)}{(x - 1)(x + 3)} = \frac{2x - 3}{x - 1} [/tex]