Matematika

Pertanyaan

Integral dari
a) (1 - 36x²) dx
b) (³√x² - ⁴√x³) dx
c) (1 + √x)² / ³√x dx

Mohon bantuannya kak!!

1 Jawaban


  • a)
    Int (1 - 36x²) dx
    = x - 12x³ + C

    b)
    Int (³√x² - ⁴√x³) dx
    = Int (x^(2/3) - x^(3/4)) dx
    = (3/5)x^(5/3) - (4/7)x^(7/4) + C

    c)
    Int (1 + √x)² / ³√x dx
    = Int (1 + 2√x + x)/x^(1/3) dx
    = Int (x^(-1/3) + x^1/6 + x^2/3) dx
    = (3/2)x^2/3 + (6/7)x^7/6 + (3/5)x^5/3 + C

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