Nomor 13 tolong sama caranya ya

gradien(m) = y' = 2x + 4
masukan x = 1
m = 2(1) + 4 = 6
x = 1 , masukan ke persamaan y
y = x² + 4x + 2
y = 1² + 4(1) + 2 = 7
(x1 , y1) = (1,7)
fungsi garis y - y1 = m(x - x1)
y - 7 = 6(x - 1)
y = 6x - 6 + 7
y = 6x + 1