hitunglah panjang ef

DC = 10
AB = 18
CF = 4
BF = 6

EF = ......

(EF - DC)/(AB - DC) = CF/BC
(EF - 10)/(18 - 10) = 4/(6 + 4)
(EF - 10)/8 = 4/10
10 × (EF - 10) = 4 × 8
10EF - 100 = 32
10EF = 32 + 100
10EF = 132
EF = 132/10
EF = 13,2


Jadi panjang EF adalah 13,2 satuan