∫ (4x^-5)^2 dx=...? ..tolong bantu saya
Matematika
ahmad894
Pertanyaan
∫ (4x^-5)^2 dx=...? ..tolong bantu saya
1 Jawaban
-
1. Jawaban SadonoSukirno
(4x^-5)^2 dx
= 4²x^(-5×2) dx
= 16x^-10 dx
= (16 / -10+1)x^(-10+1) + C
= (16/9)x^-9 + C
= (4/3)x^-9 + C
= 4 / 3x^9 + C