Matematika

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Tentukan Hp dari persamaan berikut

1) (3×+7)= ×-6
2) (2×-5/×+3)=2
3) (×-5/4)=3×-4
4) (×+7/4)=-5

2 Jawaban

  • @
    1)  3x + 7 = x - 6
    3x - x = - 6 - 7
    2x =  -13
    x = - 13/2

    2) (2x -5)/(x+3) = 2
     2x - 5 = 2(x + 3)
    2x - 5 = 2x + 6
    2x - 2x = 6 + 5
    0x = 11
    x = 11/0
    x = ~

    3) (x-5)/ 4 = 3x - 4
    x-5 = 4(3x - 4)
    x - 5 = 12x - 16
    x - 12x = -16 + 5
    -11 x = -11
    x = -11/-11
    x = 1

    4) (x+7)/ 4 = - 5
    x + 7 = 4(-5)
    x + 7 = - 20
    x = -20 -7
    x = - 27

  • 1] 3x + 7 = x - 6
    => 3x - x = -6 - 7
    => 2x = -13
    => x = -13/2
    => x = -6,5
    HP = {-6,5}

    2] (2x - 5)/(x + 3) = 2
    => 2x - 5 = 2(x + 3)
    => 2x - 5 = 2x + 6
    => 2x - 2x = 6 + 5
    => 0 = 11
    HP = { } (tidak terdefinisi)

    3](x - 5)/4 = 3x - 4
    => x - 5 = (3x - 4) × 4
    => x - 5 = 12x - 16
    => x - 12x = -16 + 5
    => -11x = -11
    => x = -11/-11
    => x = 1
    HP = {1}

    4] (x + 7)/4 = -5
    => x + 7 = -5 × 4
    => x + 7 = -20
    => x = -20 - 7
    => x = -27
    HP = {-27}

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