tentukan persamaan kurva jika diketahui : 1. dy/dx = 4x+3 dan kurva melalui titik(-2,3) 2. dy/dx = 6x²-10x+5 dan kurva melalui titik (1,7)

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y= ∫dy/dx = ∫(4x+3) dx = 2x² + 3x + c
(x,y) = (-2,3)
3 = 2(-2)² + 3(-2) + c
3 = 8 - 6 + c
3 = 2 + c
c = 1
y = 2x² + 3x + 1

y = ∫dy/dx = ∫(6x² -10x +5) dx
y = 2x³ - 5x² + 5x + c
(x,y) = (1,7)
7 = 2(1)³ -5(1)² + 5(1) + c
7 = 2 - 5 + 5 + c
7 = 2 + c
c = 5
y = 2x³ - 5x² + 5x + 5