tentukan rumus fungsi f(x) jika f'(x) =3x²+6x-7 dan f(1)=4

F(x) = ∫ 3x² + 6x - 7
        = 3/3. x²⁺¹ + 6/2. x¹⁺¹ - 7/1. x⁰⁺¹
        = x³ + 3x² - 7x
F(1) = (1)³ + 3(1)² - 7(1) + c = 4
             1 + 3 - 7 + c = 4
             -3 + c = 4
                     c = 7
maka rumus fungsi :
F(x) = x³ + 3x² - 7x + 7