mohon bantuannnya utk soal nmer 12

[tex]\displaystyle y=\frac{x-1}{2x+1} \\ 2xy+y=x-1 \\ 2xy-x=-y-1 \\ x(2y-1)=-y-1 \\ x=\frac{-y-1}{2y-1}=\frac{y+1}{1-2y} \\ $Domain:$\\ 1-2y \neq 0 \\ y \neq \frac{1}{2}[/tex]