1. koordinat titik fokus elips (x^2)/100 + (y^2)/36 = 1 adalah.. 2.koordinat titik fokus elips x^2 + 2y^2 - 4y + 2 + 0 adalah..

a = 10, b = 6
Maka c = 8
Pusat (0,0)
Fokus : (-8,0) dan (8,0)

x^2 + 2y^2 -4x - 4y + 2 = 0
(x^2-4x) + 2(y^2 - 2y) + 2 = 0
(x^2 - 4x + 4) + 2(y^2 - 2y + 1) + 2 = 4+2
(x-2)^2 + 2(y-1)^2 = 4
(x-2)^2 /4 + (y-1)^2 /2 = 1
Pusat = (2,1)
c^2 = a^2 - b^2 = 4-2 = 2
c = +- akar(2)
Fokusnya : (2-√2 ,1) dan (2+√2 ,1)