1. tentukan hasil integral tak tentu berikut a. integral √x ( x2 + 6) dx b. integral ( 2x3 - 3x2 + 1 ) : x2 dx

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^ tanda pangkat
a) √x(x² + 6) dx
= x^½ (x² + 6) dx
= (x^(½+2) + 6x^½) dx
= (x^5/2 + 6x^½) dx
= (1 / 5/2+1)x^(5/2+1) + (6 / ½+1)x^(½+1) + C
= (1 / 7/2)x^7/2 + (6 / 3/2)x^3/2 + C
= (2/7)x^7/2 + 4x^3/2 + C
= (2/7)x³√x + 4x√x + C
= √x{(2/7)x³ + 4x} + C

b) (2x³ - 3x² + 1) : x² dx
= (2x³/x² - 3x²/x² + 1/x²) dx
= (2x - 3 + x^-2) dx
= (2 / 1+1)x² - 3x + (1 / -2+1)x^(-2+1) + C
= (2/2)x² - 3x + (1/1)x^-1 + C
= x² - 3x + x^-1 + C
= x² - 3x + 1/x + C