f'(x)= (x-4)^2 , f(-2)=5

f'(x) = (x-4)^2 = x^2 - 8x + 16
diintegralkan menjadi
f(x) = (1/3)x^3 - 4x^2 + 16x + c
masukkan nilai f(-2) = 5, maka
5 = (1/3)-2^3 - 4(-2)^2 + 16(-2) + c
5 = -8/3 - 16 + (-32) + c
5 = -8/3 -48 + c
5 = (-8+144)/3 + c
5 = 136/3 + c
c = 5 - 136/3
c = (15-136)/3
c = -121/3
Maka persamaan f(x) adalah f(x) = (1/3)x^3 - 4x^2 + 16x - 121/3