tentukan f(x) jika diketahui f'(x)= -x²+2x-3 dan f(3)=0

Integral

f(x)= ∫ f '(x) dx

f(x) = ∫ (-x² + 2x - 3) dx
f(x) =  - 1/3 x³ + x² - 3x + c
f(3)= 0
-1/3(27) +(9) - (9) + c = 0
-9 + c = 0
c = 9

f(x)= - 1/3 x³ + x² - 3x + 9