y3+16y2-8y ada yg tau faktornya?

y³ + 16y² - 8y
= y(y² + 16y - 8)

y² + 16y - 8 = 0
y1.2 = (-16 ± √288)/2
y1.2 = (-8 ± 6√2)

y³ + 16y² - 8y
= y(y² + 16y - 8)
= y(y + (8 + 6√2))(y + (8 - 6√2))