1/3 + 1/6 + 1/12 + ...+1/192 = ...

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Barisan Geometri
(1/3) + (1/6) + (1/12) + ... + (1/192)
a = 1/3
r = U2/U1 = (1/6)/(1/3) = 1/2

Un = ar^(n-1)
1/192 = (1/3)(1/2)^(n-1)
1/128 = 2^-n
2^-7 = 2^-n
n = 7

(1/3) + (1/6) + (1/12) + ... + (1/192)
= S7
= a(1 - r^n)/(1 - r)
= (1/3)(1 - 1/2^7)/(1/2)
= (2/3)(2^7 - 1)/2^7
= (127)/(3 × 2^6)
= 127/192